a) \(\frac{11}{17}-\frac{5}{17}+\frac{2}{17}=\frac{11-5+2}{17}=\frac{8}{17}\)
Ответ: \(\frac{8}{17}\)
б) \(6\frac{5}{8}+2\frac{7}{8}=6+2+\frac{5}{8}+\frac{7}{8}=8+\frac{5+7}{8}=8+\frac{12}{8}=8+\frac{4 \cdot 3}{4 \cdot 2}=8+\frac{3}{2}=8+1\frac{1}{2}=9\frac{1}{2}\)
Ответ: \(9\frac{1}{2}\)
в) \(8-4\frac{5}{7}=7\frac{7}{7}-4\frac{5}{7}=(7-4)+(\frac{7}{7}-\frac{5}{7})=3+\frac{2}{7}=3\frac{2}{7}\)
Ответ: \(3\frac{2}{7}\)
г) \(7\frac{4}{15}-3\frac{11}{15}=6\frac{19}{15}-3\frac{11}{15}=(6-3)+(\frac{19}{15}-\frac{11}{15})=3+\frac{8}{15}=3\frac{8}{15}\)
Ответ: \(3\frac{8}{15}\)