135. Выполните действия: a) $$(6\frac{1}{7}-5\frac{3}{4}):\frac{11}{14} + (3\frac{3}{4}-1\frac{5}{6}):\frac{1}{6}$$; б) $$5\frac{4}{19} \cdot 3\frac{4}{7} + 1\frac{15}{19}:\frac{7}{25} - 1\frac{2}{3}$$.

Ответ (RU):

1. a) $$(6\frac{1}{7}-5\frac{3}{4}):\frac{11}{14} + (3\frac{3}{4}-1\frac{5}{6}):\frac{1}{6} = (\frac{43}{7} - \frac{23}{4}):\frac{11}{14} + (\frac{15}{4} - \frac{11}{6}):\frac{1}{6} = (\frac{43 \cdot 4 - 23 \cdot 7}{28}):\frac{11}{14} + (\frac{15 \cdot 3 - 11 \cdot 2}{12}):\frac{1}{6} = (\frac{172 - 161}{28}):\frac{11}{14} + (\frac{45 - 22}{12}):\frac{1}{6} = \frac{11}{28}:\frac{11}{14} + \frac{23}{12}:\frac{1}{6} = \frac{11}{28} \cdot \frac{14}{11} + \frac{23}{12} \cdot 6 = \frac{1}{2} + \frac{23}{2} = \frac{24}{2} = 12$$.
2. б) $$5\frac{4}{19} \cdot 3\frac{4}{7} + 1\frac{15}{19}:\frac{7}{25} - 1\frac{2}{3} = \frac{99}{19} \cdot \frac{25}{7} + \frac{34}{19}:\frac{7}{25} - \frac{5}{3} = \frac{99 \cdot 25}{19 \cdot 7} + \frac{34}{19} \cdot \frac{25}{7} - \frac{5}{3} = \frac{2475}{133} + \frac{850}{133} - \frac{5}{3} = \frac{3325}{133} - \frac{5}{3} = \frac{3325 \cdot 3 - 5 \cdot 133}{399} = \frac{9975 - 665}{399} = \frac{9310}{399} = \frac{9310}{399} \approx 23.33$$.

Перевод (RU):

1. a) $$12$$
2. б) $$\frac{9310}{399} \approx 23.33$$