a) $$ 1\frac{5}{19} \cdot (6 - 3\frac{5}{8}) = \frac{1 \cdot 19 + 5}{19} \cdot (6 - \frac{3 \cdot 8 + 5}{8}) = \frac{24}{19} \cdot (6 - \frac{29}{8}) = \frac{24}{19} \cdot (\frac{6 \cdot 8}{8} - \frac{29}{8}) = \frac{24}{19} \cdot (\frac{48}{8} - \frac{29}{8}) = \frac{24}{19} \cdot \frac{48 - 29}{8} = \frac{24}{19} \cdot \frac{19}{8} = \frac{24 \cdot 19}{19 \cdot 8} = \frac{3 \cdot 8 \cdot 19}{19 \cdot 8} = 3 $$
Ответ: 3