- a) $$\left(\frac{4}{9} + \frac{2}{9}\right) \cdot \frac{9}{13} = \frac{6}{9} \cdot \frac{9}{13} = \frac{6}{13}$$
- б) $$\frac{2}{3} \cdot \left(\frac{9}{8} - \frac{3}{4}\right) = \frac{2}{3} \cdot \left(\frac{9}{8} - \frac{6}{8}\right) = \frac{2}{3} \cdot \frac{3}{8} = \frac{1}{4}$$
- в) $$\left(\frac{9}{11} - \frac{4}{11}\right) \cdot \frac{11}{5} = \frac{5}{11} \cdot \frac{11}{5} = 1$$
- г) $$2 \cdot \frac{1}{8} + \frac{7}{12} \cdot \frac{3}{7} = \frac{1}{4} + \frac{1}{4} = \frac{1}{2}$$
- д) $$\left(\frac{2}{3}\right)^2 + \frac{13}{21} \cdot \frac{7}{26} - \frac{5}{18} = \frac{4}{9} + \frac{1}{6} - \frac{5}{18} = \frac{8}{18} + \frac{3}{18} - \frac{5}{18} = \frac{6}{18} = \frac{1}{3}$$
- е) $$\left(\frac{3}{7} - \frac{1}{7}\right)^2 \cdot \frac{49}{16} + \left(\frac{1}{2}\right)^3 = \left(\frac{2}{7}\right)^2 \cdot \frac{49}{16} + \frac{1}{8} = \frac{4}{49} \cdot \frac{49}{16} + \frac{1}{8} = \frac{1}{4} + \frac{1}{8} = \frac{3}{8}$$
Ответ: a) 6/13; б) 1/4; в) 1; г) 1/2; д) 1/3; е) 3/8