a) $$(8 - 4\frac{3}{11}) + 2\frac{8}{11} = (7\frac{11}{11} - 4\frac{3}{11}) + 2\frac{8}{11} = 3\frac{8}{11} + 2\frac{8}{11} = 5\frac{16}{11} = 5 + 1\frac{5}{11} = 6\frac{5}{11}$$
б) $$11\frac{1}{7} - (5\frac{4}{7} + 3\frac{6}{7}) = 11\frac{1}{7} - (8\frac{10}{7}) = 11\frac{1}{7} - 9\frac{3}{7} = 2\frac{1-3}{7} = 1\frac{8}{7} - \frac{3}{7} = 1\frac{5}{7}$$