1) $$\frac{9-5b}{b} - \frac{7-5c}{c} = \frac{c(9-5b)}{bc} - \frac{b(7-5c)}{bc} = \frac{9c - 5bc - 7b + 5bc}{bc} = \frac{9c - 7b}{bc}$$
Ответ: $$\frac{9c - 7b}{bc}$$