Вопрос:

What will be the output of the given Pascal and Python code snippets?

Ответ:

Let's analyze the Pascal code:

n := 0;
s := 0;
while s <= 35 do begin
n := n + 1;
s := s + 4
end;
write(n);

The code initializes n and s to 0. The while loop continues as long as s is less than or equal to 35. Inside the loop, n is incremented by 1, and s is incremented by 4. Let's trace the values:

- Initially, n = 0 and s = 0.
- Loop 1: n = 1, s = 4
- Loop 2: n = 2, s = 8
- Loop 3: n = 3, s = 12
- Loop 4: n = 4, s = 16
- Loop 5: n = 5, s = 20
- Loop 6: n = 6, s = 24
- Loop 7: n = 7, s = 28
- Loop 8: n = 8, s = 32
- Loop 9: n = 9, s = 36

The loop terminates when s becomes 36, which is greater than 35. The final value of n is 9. Therefore, the code will print 9.

Now let's analyze the Python code:

n = 0
s = 0
while s <= 35:
n += 1
s += 4
print(n)

This code does the exact same thing as the Pascal code. It initializes n and s to 0. The while loop continues as long as s is less than or equal to 35. Inside the loop, n is incremented by 1, and s is incremented by 4. Let's trace the values.

- Initially, n = 0 and s = 0.
- Loop 1: n = 1, s = 4
- Loop 2: n = 2, s = 8
- Loop 3: n = 3, s = 12
- Loop 4: n = 4, s = 16
- Loop 5: n = 5, s = 20
- Loop 6: n = 6, s = 24
- Loop 7: n = 7, s = 28
- Loop 8: n = 8, s = 32
- Loop 9: n = 9, s = 36

The loop terminates when s becomes 36, which is greater than 35. The final value of n is 9. Therefore, the code will print 9.

Answer: 9
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