Let's analyze the Pascal code:
n := 0;
s := 0;
while s <= 35 do begin
n := n + 1;
s := s + 4
end;
write(n);
The code initializes n
and s
to 0. The while
loop continues as long as s
is less than or equal to 35. Inside the loop, n
is incremented by 1, and s
is incremented by 4. Let's trace the values:
- Initially, n = 0
and s = 0
.
- Loop 1: n = 1
, s = 4
- Loop 2: n = 2
, s = 8
- Loop 3: n = 3
, s = 12
- Loop 4: n = 4
, s = 16
- Loop 5: n = 5
, s = 20
- Loop 6: n = 6
, s = 24
- Loop 7: n = 7
, s = 28
- Loop 8: n = 8
, s = 32
- Loop 9: n = 9
, s = 36
The loop terminates when s
becomes 36, which is greater than 35. The final value of n
is 9. Therefore, the code will print 9.
Now let's analyze the Python code:
n = 0
s = 0
while s <= 35:
n += 1
s += 4
print(n)
This code does the exact same thing as the Pascal code. It initializes n
and s
to 0. The while
loop continues as long as s
is less than or equal to 35. Inside the loop, n
is incremented by 1, and s
is incremented by 4. Let's trace the values.
- Initially, n = 0
and s = 0
.
- Loop 1: n = 1
, s = 4
- Loop 2: n = 2
, s = 8
- Loop 3: n = 3
, s = 12
- Loop 4: n = 4
, s = 16
- Loop 5: n = 5
, s = 20
- Loop 6: n = 6
, s = 24
- Loop 7: n = 7
, s = 28
- Loop 8: n = 8
, s = 32
- Loop 9: n = 9
, s = 36
The loop terminates when s
becomes 36, which is greater than 35. The final value of n
is 9. Therefore, the code will print 9.
Answer: 9