5) x2 - xy + 2xy-3x2 x²y x²y

5) $$\frac{x^2 - xy}{x^2y} + \frac{2xy - 3x^2}{x^2y} = \frac{x^2 - xy + 2xy - 3x^2}{x^2y} = \frac{-2x^2 + xy}{x^2y} = \frac{x(-2x + y)}{x^2y} = \frac{y - 2x}{xy}.$$

Ответ: $$\frac{y-2x}{xy}$$