3)4-x-3-x-1= 7 3 7 4 x x = 32 4 32 4

з) $$4\frac{7}{32}x - \left(3\frac{3}{4}x - 1\frac{7}{32}x\right) = 4\frac{7}{32}x - 3\frac{3}{4}x + 1\frac{7}{32}x = 4\frac{7}{32}x - 3\frac{24}{32}x + 1\frac{7}{32}x = (4-3+1 + \frac{7-24+7}{32})x = 2-\frac{10}{32}x = 1\frac{32-10}{32}x = 1\frac{22}{32}x = 1\frac{11}{16}x$$

Ответ: $$1\frac{11}{16}x$$