2) (6xy)⁶⋅((1/3)x²)⁶⋅(-4y³)⁶;

2) $$(6xy)^6 \cdot ((\frac{1}{3})x^2)^6 \cdot (-4y^3)^6 = 6^6x^6y^6 \cdot (\frac{1}{3})^6x^{12} \cdot (-4)^6y^{18} = 6^6 \cdot (\frac{1}{3})^6 \cdot (-4)^6 \cdot x^6 \cdot x^{12} \cdot y^6 \cdot y^{18} = \frac{6^6}{3^6} \cdot 4^6 \cdot x^{18}y^{24} = 2^6 \cdot 4^6 \cdot x^{18}y^{24} = 2^6 \cdot (2^2)^6 \cdot x^{18}y^{24} = 2^6 \cdot 2^{12} \cdot x^{18}y^{24} = 2^{18}x^{18}y^{24}$$

Ответ: $$2^{18}x^{18}y^{24}$$