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МатематикаВопрос:
ятнадцать 19=10+9
Ответ:
Девятнадцать = 10 + 9
Ответ: 19
Похожие
- Iдес 5 eg = 95
- I gec teg =71
- zgec 6 eg = 26
- 8 gec 8 eg =88
- Здес дед =39
- здес+ 4 дес= 7 gec
- 9 дес- 3 дес=7
- 5\(\frac{3}{14}\)+3\(\frac{1}{12}\)=5\(\frac{18}{84}\)+3\(\frac{7}{84}\)=8\(\frac{25}{84}\)
- 1\(\frac{1}{12}\)+3\(\frac{14}{15}\)=\(\frac{55}{60}\)+3\(\frac{56}{60}\)=3\(\frac{111}{60}\)=3+1\(\frac{51}{60}\)=4\(\frac{51}{60}\)
- 3\(\frac{1}{12}\)+7\(\frac{13}{14}\)=3\(\frac{7}{84}\)+7\(\frac{78}{84}\)=10\(\frac{85}{84}\)=10+1\(\frac{1}{84}\)=11\(\frac{1}{84}\)
- 14\(\frac{3}{5}\)-2\(\frac{1}{2}\)=14\(\frac{6}{10}\)-\(\frac{25}{10}\)=12\(\frac{1}{10}\)
- 23\(\frac{5}{6}\)-2\(\frac{13}{15}\)=23\(\frac{25}{30}\)-2\(\frac{12}{30}\)=21\(\frac{13}{30}\)
- 17\(\frac{3}{5}\)-7\(\frac{1}{4}\)=17\(\frac{12}{20}\)-\(\frac{75}{20}\)=10\(\frac{7}{20}\)
- 14\(\frac{3}{18}\)+5\(\frac{3}{4}\)=14\(\frac{6}{36}\)+5\(\frac{27}{36}\)=19\(\frac{33}{36}\)
- 2\(\frac{13}{16}\)+5\(\frac{1}{2}\)=2\(\frac{13}{16}\)+5\(\frac{8}{16}\)=7\(\frac{21}{16}\)=7+1\(\frac{5}{16}\)=8\(\frac{5}{10}\)
- 8\(\frac{5}{12}\)+2\(\frac{9}{30}\)=8\(\frac{25}{60}\)+\(\frac{58}{60}\)=8\(\frac{83}{60}\)=8+1\(\frac{23}{60}\)=9\(\frac{23}{60}\)
- 16\(\frac{4}{5}\)-3\(\frac{1}{6}\)=16\(\frac{24}{30}\)-3\(\frac{5}{30}\)=13\(\frac{19}{30}\)
- 24\(\frac{1}{7}\)-12\(\frac{1}{12}\)=24\(\frac{12}{84}\)-12\(\frac{7}{84}\)=12\(\frac{5}{84}\)
- 18\(\frac{5}{21}\)-11\(\frac{3}{14}\)=18\(\frac{10}{42}\)-11\(\frac{9}{42}\)=7\(\frac{1}{42}\)
- дцать 18=10+8
