y-31-y + 9y 2y B)

Решение:

$$\frac{y-3}{9y} + \frac{1-y}{2y} = \frac{2(y-3)+9(1-y)}{18y} = \frac{2y-6+9-9y}{18y} = \frac{-7y+3}{18y}$$

Ответ:

$$\frac{-7y+3}{18y}$$