Краткое пояснение: Выполняем действия в скобках, затем умножение и деление, сложение и вычитание.
- \(\frac{1}{2}\cdot(\frac{5}{8}-\frac{8}{3})-2\cdot1\frac{3}{7} = \frac{1}{2} \cdot (\frac{15-64}{24}) - 2 \cdot \frac{10}{7} = \frac{1}{2} \cdot (-\frac{49}{24}) - \frac{20}{7} = -\frac{49}{48} - \frac{20}{7} = \frac{-49 \cdot 7 - 20 \cdot 48}{336} = \frac{-343 - 960}{336} = -\frac{1303}{336}\)
- \((7-\frac{5}{9}:\frac{7}{24}):\frac{20}{27} = (7 - \frac{5}{9} \cdot \frac{24}{7}) : \frac{20}{27} = (7 - \frac{5 \cdot 8}{3 \cdot 7}) : \frac{20}{27} = (7 - \frac{40}{21}) : \frac{20}{27} = \frac{147 - 40}{21} : \frac{20}{27} = \frac{107}{21} \cdot \frac{27}{20} = \frac{107 \cdot 9}{7 \cdot 20} = \frac{963}{140}\)
- \(\frac{31}{35}:((\frac{2}{8}-\frac{19}{45}):\frac{1}{5}) = \frac{31}{35} : ((\frac{1}{4} - \frac{19}{45}) : \frac{1}{5}) = \frac{31}{35} : ((\frac{45 - 19 \cdot 4}{180}) : \frac{1}{5}) = \frac{31}{35} : ((\frac{45 - 76}{180}) : \frac{1}{5}) = \frac{31}{35} : (\frac{-31}{180} \cdot 5) = \frac{31}{35} : \frac{-31}{36} = \frac{31}{35} \cdot \frac{-36}{31} = -\frac{36}{35}\)
- \((\frac{5}{16}-\frac{1}{8}):(\frac{5}{6}+\frac{3}{14}) = (\frac{5-2}{16}) : (\frac{5 \cdot 7 + 3 \cdot 3}{42}) = \frac{3}{16} : \frac{35 + 9}{42} = \frac{3}{16} : \frac{44}{42} = \frac{3}{16} \cdot \frac{21}{22} = \frac{3 \cdot 21}{16 \cdot 22} = \frac{63}{352}\)
Ответ: -1303/336; 963/140; -36/35; 63/352