Ответ:
Используем обозначения \(P_n=n!\), \(A_n^k=\frac{n!}{(n-k)!}\), \(C_n^k=\frac{n!}{k!(n-k)!}\).
- \(P_7=5040;\ A_{10}^3=720;\ C_8^4=70\).
- \(P_8=40320;\ A_9^4+C_7^2=3024+21=3045\).
- \(P_9=362880;\ A_{10}^3+C_8^4=720+70=790\).
- \(720+70=790\).
- \(6-20+21=7\).
- \(24+12-56=-20\).
- \(56+35=91\).
- \(210+126=336\).
- \(120-42+20=98\).
- \(5040+336+35=5411\).
- \(40320+1680+15=42015\).
- \(24+60+126=210\).
- \(720+70=790\).
- \(5040-90+126=5076\).
- \(720+72-126=666\).
- \(56+35=91\).
- \(210+126=336\).
- \(120-72+6=54\).
- \(5040+720+70=5830\).
- \(40320+3024+21=43365\).
- \(362880+60+70=363010\).
- \(120+56=176\).
- \(120-3024+45=-2859\).
- \(720+42-28=734\).
- \(120-42+20=98\).
