Задание 340 (найти значения выражений):

Решения представлены ниже для каждого пункта: а) \(3k + 0.5(1 - 6k) - (7 - 6k)\): - При \(k = 0.05\): \(3 \cdot 0.05 + 0.5(1 - 6 \cdot 0.05) - (7 - 6 \cdot 0.05) = 0.15 + 0.5 \cdot 0.7 - 6.7 = 0.5 - 6.7 = -6.2\). - При \(k = -1.2\): \(3(-1.2) + 0.5(1 - 6(-1.2)) - (7 - 6(-1.2)) = -3.6 + 0.5 \cdot 8.2 - (-0.8) = 0.1\). - При \(k = 10\): \(3(10) + 0.5(1 - 6(10)) - (7 - 6(10)) = 30 - 29.5 + 53 = 53.5\). б) \(x(y - 1) - y(x + 1)\): - При \(x = 1, y = \frac{2}{3}\): \(1(\frac{2}{3} - 1) - \frac{2}{3}(1 + 1) = -\frac{4}{3}\). - При \(x = -\frac{1}{5}, y = -0.6\): \(-\frac{1}{5}(-0.6 - 1) - (-0.6)(-\frac{1}{5} + 1) = \frac{7}{25}\). в) \(c(b + c) - b(a - c) + c(b - c) + ab\): - При \(b = 0.3, c = -\frac{1}{9}\): \(-\frac{1}{9}(0.3 - \frac{1}{9}) - 0.3(-\frac{1}{9}) = -\frac{1}{15}\). - При \(b = -0.25, c = -\frac{2}{15}\): \(-\frac{2}{15}(-0.25 - \frac{2}{15}) - (-0.25)(-\frac{2}{15}) = \frac{2}{25}\).