Задание 7. Выполните действия: а) 10+2 1/6; 5/11+4 2/11; 6 2/9+1 1/9; 3/5+5 2/5; 3 7/13+3 9/13; 4 17/24+2 11/24. б) 3 7/8−3; 8 3/10−3/10; 7 5/6−2 1/6; 9−8/15; 6−3 5/7; 5 1/3−1 2/3. в) 5 1/3+2; 3 2/9+5 5/9; 8 8/11−5/11; 2 5/8+2 7/8; 10−4 3/10; 6 2/7−3 6/7.
- а) \(10+2\frac{1}{6}=12\frac{1}{6}\); \(\frac{5}{11}+4\frac{2}{11}=4\frac{7}{11}\); \(6\frac{2}{9}+1\frac{1}{9}=7\frac{3}{9}=7\frac{1}{3}\); \(\frac{3}{5}+5\frac{2}{5}=5\); \(3\frac{7}{13}+3\frac{9}{13}=6\frac{16}{13}=7\frac{3}{13}\); \(4\frac{17}{24}+2\frac{11}{24}=6\frac{28}{24}=7\frac{1}{6}\).
- б) \(3\frac{7}{8}-3=\frac{7}{8}\); \(8\frac{3}{10}-\frac{3}{10}=8\); \(7\frac{5}{6}-2\frac{1}{6}=5\frac{4}{6}=5\frac{2}{3}\); \(9-\frac{8}{15}=8\frac{7}{15}\); \(6-3\frac{5}{7}=2\frac{2}{7}\); \(5\frac{1}{3}-1\frac{2}{3}=3\frac{2}{3}\).
- в) \(5\frac{1}{3}+2=7\frac{1}{3}\); \(3\frac{2}{9}+5\frac{5}{9}=8\frac{7}{9}\); \(8\frac{8}{11}-\frac{5}{11}=8\frac{3}{11}\); \(2\frac{5}{8}+2\frac{7}{8}=5\frac{12}{8}=6\frac{1}{2}\); \(10-4\frac{3}{10}=5\frac{7}{10}\); \(6\frac{2}{7}-3\frac{6}{7}=2\frac{3}{7}\).