ГДЗ по алгебре 7 класс Макарычев ФГОС Задание 1113

\[\boxed{\text{1113.}\text{\ }еуроки - ответы\ на\ пятёрку}\]

\[\textbf{а)}\ 15a² - 15b^{2} =\]

\[= 15 \cdot \left( a^{2} - b^{2} \right) =\]

\[= 15 \cdot (a - b)(a + b)\]

\[\textbf{б)}\ 29a^{2} + 29b^{2} + 58ab = 29 \cdot\]

\[\cdot \left( a^{2} + 2ab + b^{2} \right) =\]

\[= 29 \cdot (a + b)^{2} =\]

\[= 29 \cdot (a + b)9a + b)\]

\[\textbf{в)}\ 10a³ + 10b³ = 10 \cdot\]

\[\cdot \left( a^{3} + b^{3} \right) = 10 \cdot\]

\[\cdot (a + b)(a^{2} - ab + b^{2})\]

\[\textbf{г)}\ 18a³ - 18b^{3} = 18 \cdot\]

\[\cdot \left( a^{3} - b^{3} \right) = 18 \cdot\]

\[\cdot (a - b)(a^{2} + ab + b^{2})\]

\[\textbf{д)}\ 47a^{6} - 47b^{6} = 47 \cdot\]

\[\cdot \left( a^{6} - b^{6} \right) = 47 \cdot\]

\[\cdot \left( a^{3} - b^{3} \right)\left( a^{3} + b^{3} \right) =\]

\[= 47 \cdot (a - b)\left( a^{2} + ab + b^{2} \right)\]

\[(a + b)\left( a^{2} - ab + b^{2} \right)\]

\[\textbf{е)}\ 51a^{6} + 51b^{6} = 51 \cdot\]

\[\cdot \left( a^{6} + b^{6} \right) = 51 \cdot\]

\[\cdot \left( a^{2} + b^{2} \right)\left( a^{4} - a^{2}b^{2} + b^{4} \right)\]