ГДЗ по алгебре 7 класс Макарычев ФГОС Задание 910

\[\boxed{\text{910.}\text{\ }еуроки - ответы\ на\ пятёрку}\]

\[а\ (x + 3)^{2} - 1 = (x + 3 - 1)(x + 3 + 1) = (x + 2)(x + 4)\]

\[\textbf{б)}\ 64 - (b + 1)^{2} = (8 - b - 1)(8 + b + 1) = (7 - b)(9 + b)\]

\[\textbf{в)}\ (4a - 3)^{2} - 16 = (4a - 3 - 4)(4a - 3 + 4) = (4a - 7)(4a + 1)\]

\[\textbf{г)}\ 25 - (a + 7)^{2} = (5 - a - 7)(5 + a + 7) = ( - 2 - a)(12 + a)\]

\[\textbf{д)}\ (5y - 6)^{2} - 81 = (5y - 6 - 9)(5y - 6 + 9) = (5y - 15)(5y + 3) =\]

\[= 5 \cdot (y - 3)(5y + 3)\]

\[\textbf{е)}\ 1 - (2x - 1)^{2} = (1 - 2x + 1)(1 + 2x - 1) = (2 - 2x) \cdot 2x = 4x(1 - x)\]