ГДЗ по алгебре 8 класс Макарычев Задание 105

\[\boxed{\text{105\ (105).\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

\[y = \frac{2x - 5}{3}\]

\[x = - 2:\]

\[\text{y\ }( - 2) = \frac{2 \cdot ( - 2) - 5}{3} =\]

\[= \frac{- 4 - 5}{3} = - \frac{9}{3} = - 3.\]

\[x = 0:\]

\[\text{y\ }(0) = \frac{2 \cdot 0 - 5}{3} = \frac{0 - 5}{3} =\]

\[= - \frac{5}{3} = - 1\frac{2}{3}.\]

\[x = 16:\]

\[\text{y\ }(16) = \frac{2 \cdot 16 - 5}{3} = \frac{32 - 5}{3} =\]

\[= \frac{27}{3} = 9.\]

\[y = 3:\]

\[2x - 5 = 9\]

\[2x = 14\]

\[x = 7.\]

\[y = 0:\]

\[2x - 5 = 0\]

\[2x = 5\]

\[x = 2,5.\]

\[y = - 9:\]

\[2x - 5 = - 27\]

\[2x = - 22\]

\[x = - 11.\]