ГДЗ по алгебре 8 класс Макарычев Задание 415

\[\boxed{\text{415\ (415).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

Пояснение.

Решение.

\[\textbf{а)}\ \frac{1}{3}\sqrt{351} < \frac{1}{2}\sqrt{188}\]

\[\sqrt{\frac{1}{9} \cdot 351} < \sqrt{\frac{1}{4} \cdot 188}\]

\[\sqrt{39} < \sqrt{47}\]

\[\textbf{б)}\ \frac{1}{3}\sqrt{54} = \frac{1}{5}\sqrt{150}\]

\[\sqrt{\frac{1}{9} \cdot 54} = \sqrt{\frac{1}{25} \cdot 150}\]

\[\sqrt{6} = \sqrt{6}\]

\[\textbf{в)}\ \sqrt{24} = \frac{1}{3}\sqrt{216}\]

\[\sqrt{24} = \sqrt{\frac{1}{9} \cdot 216}\]

\[\sqrt{24} = \sqrt{24}\]

\[\textbf{г)}\frac{2}{3}\sqrt{72} < 7\sqrt{\frac{2}{3}}\]

\[\sqrt{\frac{4}{9} \cdot 72} < \sqrt{49 \cdot \frac{2}{3}}\]

\[\sqrt{32} < \sqrt{\frac{98}{3}} = \sqrt{32\frac{2}{3}}\]