\[\boxed{\text{73\ (73).\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]
Пояснение.
Решение.
\[= \frac{3x}{6} + \frac{2y}{6} = \frac{3x + 2y}{6}\ \]
\[= \frac{3c}{12} - \frac{d}{12} = \frac{3c - d}{12}\]
\[= \frac{a^{2} - b^{3}}{\text{ab}}\]
\[= \frac{9 - 4}{6x} = \frac{5}{6x}\]
\[= \frac{5x + 2x}{8y} = \frac{7x}{8y}\]
\[\textbf{е)}\ \frac{17y^{\backslash 3}}{24c} - \frac{25y^{\backslash 2}}{36c} =\]
\[= \frac{51y - 50y}{72c} = \frac{y}{72c}\]
\[= \frac{5 - 8}{25a} = - \frac{3}{25a}\]
\[\textbf{з)}\ \frac{3b^{\backslash b}}{4c} + \frac{c^{\backslash 2c}}{2b} =\]