ГДЗ по алгебре 8 класс Макарычев Задание 74

\[\boxed{\text{74\ (74).\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

Пояснение.

Решение.

\[\textbf{а)}\ \frac{5y - 3^{\backslash 2}}{6y} + \frac{y + 2^{\backslash 3}}{4y} =\]

\[= \frac{2 \cdot (5y - 3) + 3 \cdot (y + 2)}{12y}\]

\[= \frac{10y - 6 + 3y + 6}{12y} = \ \frac{13y}{12y} =\]

\[= \frac{13}{12} = 1\frac{1}{12}\]

\[\textbf{б)}\ \frac{3x + 5^{\backslash 3}}{35x} + \frac{x - 3^{\backslash 5}}{21x} =\]

\[= \frac{9x + 15 + 5x - 15}{105x} =\]

\[= \frac{14x}{105x} = \frac{2}{15}\]

\[\textbf{в)}\ \frac{b + 2^{\backslash 3c}}{15b} - \frac{3c - 5^{\backslash b}}{45c} =\]

\[= \frac{3bc + 6c - 3bc + 5b}{45cb} =\]

\[= \frac{6c + 5b}{45bc}\]

\[\textbf{г)}\ \frac{8b + y^{\backslash 3y}}{40b} - \frac{6y + b^{\backslash 4b}}{30y} =\]

\[= \frac{24by + 3y^{2} - 24by - 4b^{2}}{120by} =\]

\[= \frac{3y^{2} - 4b^{2}}{120by}\]