\[\boxed{\text{342\ (342).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]
\[1)y = \frac{9x - 18}{x^{2} - 2x}\]
\[\frac{9x - 18}{x^{2} - 2x} = \frac{9 \cdot (x - 2)}{x(x - 2)} = \frac{9}{x}\]
\[y = \frac{9}{x};\ \ при\ x \neq 2\]
\[x\] | \[2\] | \[4,5\] | \[3\] | \[- 2\] | \[- 4,5\] | \[- 3\] |
---|---|---|---|---|---|---|
\[y\] | \[4,5\] | \[2\] | \[3\] | \[- 4,5\] | \[- 2\] | \[- 3\] |
\[2)\ y = \frac{5x^{2} - 5}{x - x^{3}}\]
\[\frac{5x^{2} - 5}{x - x^{3}} = \frac{5\left( x^{2} - 1 \right)}{x\left( 1 - x^{2} \right)} = - \frac{5}{x}\]
\[y = - \frac{5}{x};\ \ при\ x \neq 1;\ \ x \neq - 1\]
\[x\] | \[1\] | \[2\] | \[5\] | \[- 1\] | \[- 2\] | \[- 5\] |
---|---|---|---|---|---|---|
\[y\] | \[- 5\] | \[- 2,5\] | \[- 1\] | \[5\] | \[2,5\] | \[1\] |