ГДЗ по алгебре 9 класс Макарычев Задание 383

\[\boxed{\text{383\ (383).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

\[x^{2} + 6x - 7 \leq 0\]

\[D_{1} = 3^{2} + 7 = 16\]

\[x_{1,2} = - 3 \pm 4\]

\[x_{1} = - 7;\ \ x_{2} = 1.\]

\[(x + 7)(x - 1) \leq 0\]

\[\Longrightarrow x \in \lbrack - 7;1\rbrack.\]

\[x^{2} - 2x - 15 \leq 0\]

\[D = 1 + 15 = 16\]

\[x_{1,2} = 1 \pm 4\]

\[x_{1} = - 3;\ \ x_{2} = 1.\]

\[(x + 3)(x - 1) \leq 0\]

\[\Longrightarrow x \in \lbrack - 3;1\rbrack.\]

\[Общее\ решение:\ x \in \lbrack - 3;1\rbrack.\]