ГДЗ по геометрии 7 класс Атанасян Задание 1039

\[\boxed{\mathbf{1039.ОК\ ГДЗ - домашка\ на}\ 5}\]

\[Рисунок\ по\ условию\ задачи:\]

\[\mathbf{Дано:}\]

\[ABCD - квадрат;\]

\[AC \cap DB = O.\]

\[\mathbf{Найти:}\]

\[угол\ между\ векторами.\]

\[\mathbf{Решение.}\]

\[\textbf{а)}\ \left( \widehat{\overrightarrow{\text{AB}};\overrightarrow{\text{AC}}} \right) = 45{^\circ};\]

\[\textbf{б)}\ \left( \widehat{\overrightarrow{\text{AB}};\overrightarrow{\text{DA}}} \right) = 90{^\circ};\]

\[\textbf{в)}\ \left( \widehat{\overrightarrow{\text{OA}};\overrightarrow{\text{OB}}} \right) = 90{^\circ};\]

\[\textbf{г)}\ \left( \widehat{\overrightarrow{\text{AO}};\overrightarrow{\text{OB}}} \right) = 90{^\circ};\]

\[\textbf{д)}\ \left( \widehat{\overrightarrow{\text{OA}};\overrightarrow{\text{OC}}} \right) = 180{^\circ};\]

\[\textbf{е)}\ \left( \widehat{\overrightarrow{\text{AC}};\overrightarrow{\text{BD}}} \right) = 90{^\circ};\]

\[\textbf{ж)}\ \left( \widehat{\overrightarrow{\text{AD}};\overrightarrow{\text{DB}}} \right) = 135{^\circ};\]

\[\textbf{з)}\ \left( \widehat{\overrightarrow{\text{AO}};\overrightarrow{\text{OC}}} \right) = 0{^\circ}.\]