\[\boxed{\mathbf{37.}\mathbf{ОК\ ГДЗ - домашка\ на}\ 5}\]
\[Рисунок\ по\ условию\ задачи:\]
\[Дано:\]
\[\textbf{а)}\ AB = 2\ см\]
\[\textbf{б)}\ CB = 3,2\ м\]
\[Найти:\]
\[\textbf{а)}\ \text{AC},\ \text{CB},\ \text{AO},\ \text{OB}\]
\[\textbf{б)}\ \text{AB},\ \text{AC},\ \text{AO},\ \text{OB}\]
\[Решение.\]
\[\textbf{а)}\ CB = AB\ :2 = 2\ см\ :2 =\]
\[= 1\ см.\]
\[AC = CB = 1\ см\]
\[AO = AC\ :2 = 1\ см\ :2 = 0,5\ см.\]
\[OC = AO = 0,5\ см\]
\[OB = CB + OC =\]
\[= 1\ см + 0,5\ см = 1,5\ см.\]
\[\textbf{б)}\ AC = CB = 3,2\ м\]
\[AB = AC + CB =\]
\[= 3,2\ м + 3,2\ м = 6,4\ м.\]
\[AO = AC\ :2 = 3,2\ м\ :2 = 1,6\ м.\]
\[OC = AO = 1,6\ м\]
\[\text{OB} = \text{CB} + \text{OC} =\]
\[= 3,2\ м + 1,6\ м = 4,8\ м.\]
\[Ответ:а)\ AC = 1\ см;\ CB = 1\ см;\ \]
\[AO = 0,5\ см;\ OB = 1,5\ см;\]
\[\textbf{б)}\ AB = 6,4\ м;\ AC = 3,2\ м;\ \]
\[AO = 1,6\ м;\ OB = 4,8\ м.\]