ГДЗ по математике 3 класс Моро ФГОС Часть 1, 2 Часть 2 | Страница 14

\[Страница\ 14.\]

Вычисли (стр. 14)

\[\boxed{\mathbf{Вычисли}\mathbf{.}\mathbf{\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[64\ :4 = (40 + 24)\ :4 =\]

\[= 40\ :4 + 24\ :4 = 10 + 6 = 16\]

\[7 \cdot 12 = 7 \cdot (10 + 2) = 7 \cdot 10 +\]

\[+ 7 \cdot 2 = 70 + 14 = 84\]

\[50\ :2 = (40 + 10)\ :2 =\]

\[= 40\ :2 + 10\ :2 = 20 + 5 = 25\]

\[39\ :3 = (30 + 9)\ :3 = 30\ :3 +\]

\[+ 9\ :3 = 10 + 3 = 13\]

\[\boxed{\mathbf{1}\mathbf{.}\mathbf{\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[72 = 40 + 32\]

\[72\ :4 = (40 + 32)\ :4 = 40\ :4 +\]

\[+ 32\ :4 = 10 + 8 = 18\]

\[72 = 60 + 12\]

\[72\ :3 = (60 + 12)\ :3 = 60\ :3 +\]

\[+ 12\ :3 = 20 + 4 = 24\]

\[72 = 36 + 36\]

\[72\ :6 = (36 + 36)\ :6 =\]

\[= 36\ :6 + 36\ :6 = 6 + 6 = 12\]

\[\boxed{\mathbf{2}\mathbf{.}\mathbf{\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[84\ :6 = (60 + 24)\ :6 =\]

\[= 60\ :6 + 24\ :6 = 10 + 4 = 14\]

\[57\ :3 = (30 + 27)\ :3 =\]

\[= 30\ :3 + 27\ :3 = 10 + 9 = 19\]

\[91\ :7 = (70 + 21)\ :7 =\]

\[= 70\ :7 + 21\ :7 = 10 + 3 = 13\]

\[3 \cdot 18 = 3 \cdot (10 + 8) = 3 \cdot 10 +\]

\[+ 3 \cdot 8 = 30 + 24 = 54\]

\[4 \cdot 17 = 4 \cdot (10 + 7) = 4 \cdot 10 +\]

\[+ 4 \cdot 7 = 40 + 28 = 68\]

\[6 \cdot 13 = 6 \cdot (10 + 3) = 6 \cdot 10 +\]

\[+ 6 \cdot 3 = 60 + 18 = 78\]

\[86\ :2 = (80 + 6)\ :2 = 80\ :2 +\]

\[+ 6\ :2 = 40 + 3 = 43\]

\[60\ :4 = (40 + 20)\ :4 =\]

\[= 40\ :4 + 20\ :4 = 10 + 5 = 15\]

\[93\ :3 = (90 + 3)\ :3 = 90\ :3 +\]

\[+ 3\ :3 = 30 + 1 = 31\]

\[68\ :2 = (60 + 8)\ :2 = 60\ :2 +\]

\[+ 8\ :2 = 30 + 4 = 34\]

\[96\ :3 = (90 + 6)\ :3 = 90\ :3 +\]

\[+ 6\ :3 = 30 + 2 = 32\]

\[88\ :4 = (44 + 44)\ :4 = 44\ :4 +\]

\[+ 44\ :4 = 11 + 11 = 22\]

\[\boxed{\mathbf{3}\mathbf{.}\mathbf{\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1)\ 6 \cdot 4 = 24\ (кг) - винограда\ \]

\[в\ 4\ корзинах.\]

\[2)\ 32 - 24 = 8\ (кг) -\]

\[винограда\ в\ пятой\ корзине.\]

\[Ответ:\ \ на\ 15.\]

\[\boxed{\mathbf{4}\mathbf{.}\mathbf{\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[Цена\ билета\ 30\ рублей.\ \]

\[Пассажир\ отдал\ в\ кассу\ 100\ \]

\[рублей\ для\ покупки\ \]

\[трех\ билетов.\]

\[1)\ 30 \cdot 3 = 90\ (рублей) - стоят\]

\[\ три\ билета.\]

\[2)\ 100 - 90 = 10\ (рублей) -\]

\[сдача.\]

\[Ответ:\ \ 10\ рублей.\]

\[\boxed{\mathbf{5}\mathbf{.}\mathbf{\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[39\ :3 \cdot 4 = 13 \cdot 4 = 52\]

\[64\ :2 \cdot 3 = 32 \cdot 3 = 96\]

\[48\ :4 \cdot 8 = 12 \cdot 8 = 96\]

\[100 - 3 \cdot 4 = 100 - 12 = 88\]

\[6 \cdot 9 + 48\ :6 = 54 + 8 = 62\]

\[66\ :3 \cdot 2 - 5 = 22 \cdot 2 - 5 =\]

\[= 44 - 5 = 39\]

\[84 - (48 + 26) = 84 - 74 = 10\]

\[23 + (75 - 48) = 23 + 27 = 50\]

\[53 - (53 - 40) =\]

\[= 53 - 53 + 40 = 40\]

\[\boxed{\mathbf{6}\mathbf{.}\mathbf{\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[L_{\text{ABCD}} = 3 + 3 + 1 = 7\ см.\]

\[L_{\text{KOCEM}} = 25 + 20 + 20 + 25 =\]

\[= 90\ мм = 9\ см.\]

\[L_{\text{ABCD}} < L_{\text{KOCEM}}.\]

\[\boxed{\mathbf{7}\mathbf{.}\mathbf{\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[Прямые\ углы:\ \ \angle B;\ \ \ \angle C;\ \ \ \angle T;\ \]

\[\ \ \angle K.\]

\[Тупые\ углы:\ \ \angle A;\ \ \ \angle M;\ \ \angle D;\ \ \]

\[\angle O;\ \ \ \angle E.\]

\[Острые\ углы:\ \angle P;\ \ \angle S;\ \ \angle N.\]