§ Задание 44
\[\boxed{\mathbf{44}\mathbf{.}}\]

\[\textbf{б)}\ 45 + 12 - 0 = 57 - 0 = 57\]
\[73 - (30 - 0) = 73 - 30 = 43\]
\[100 - 1 - 99 = 99 - 99 = 0\]
\[\boxed{\mathbf{44}\mathbf{.}}\]

\[\textbf{б)}\ 45 + 12 - 0 = 57 - 0 = 57\]
\[73 - (30 - 0) = 73 - 30 = 43\]
\[100 - 1 - 99 = 99 - 99 = 0\]