\(Страница\ 11.\)
\[\boxed{\mathbf{2.}}\]
\[\textbf{а)}\ \frac{2}{3} > \frac{1}{3}\]
\[\textbf{б)}\ \frac{3}{7} < \frac{5}{7}\]
\[\textbf{в)}\ \frac{1}{2} = \frac{3}{6}\]
\[\textbf{г)}\ \frac{7}{10} < \frac{9}{10}\]
\[\textbf{д)}\ \frac{5}{100} > \frac{3}{100}\]
\[\textbf{е)}\ \frac{4}{8} = \frac{3}{6}\]
\[\boxed{\mathbf{3.}}\]
\[\textbf{а)}\ \frac{5}{8}\]
\[\textbf{б)}\ \frac{2}{3}\]
\[\textbf{в)}\ \frac{9}{10}\]
\[\textbf{г)}\ \frac{7}{30}\]
\[\textbf{д)}\ \frac{1}{10}\]
\[\textbf{е)}\ \frac{1}{100}\]
\[\boxed{\mathbf{4.}}\]
\[\frac{2}{10};\ \frac{3}{10};\ \frac{4}{10};\ \frac{5}{10};\ \frac{6}{10};\ \frac{7}{10};\ \frac{8}{10}.\]