ГДЗ по математике 5 класс Ерина рабочая тетрадь Часть 1, 2 Часть 2 | Страница 26

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\[\boxed{\mathbf{3.}}\]

\[\textbf{б)}\ \frac{20}{7} = 2\frac{6}{7}\]

\[\textbf{в)}\ \frac{38}{6} = 6\frac{2}{6}\]

\[\textbf{г)}\ \frac{13}{7} = 1\frac{6}{7}\]

\[\textbf{д)}\ \frac{30}{4} = 7\frac{2}{4}\]

\[\textbf{е)}\ \frac{48}{5} = 9\frac{3}{5}\]

\[\textbf{ж)}\ \frac{19}{3} = 6\frac{1}{3}\]

\[\textbf{з)}\ \frac{58}{5} = 11\frac{3}{5}\]

\[\textbf{и)}\ \frac{203}{10} = 20\frac{3}{10}\]

\[\boxed{\mathbf{4.}}\]

\[\textbf{а)}\ 1\frac{2}{3} = \frac{5}{3}\]

\[\textbf{б)}\ 4\frac{3}{7} = \frac{31}{7}\]

\[\textbf{в)}\ 8\frac{1}{9} = \frac{73}{9}\]

\[\textbf{г)}\ 10\frac{2}{11} = \frac{112}{11}\]

\[\textbf{д)}\ 3\frac{1}{100} = \frac{301}{100}\]

\[\textbf{е)}\ 7\frac{3}{5} = \frac{38}{5}\]

\[\textbf{ж)}\ 6\frac{1}{9} = \frac{55}{9}\]

\[\textbf{з)}\ 20\frac{3}{17} = \frac{343}{17}\]

\[\textbf{и)}\ 4\frac{2}{9} = \frac{38}{9}\]

\[к)\ 5\frac{1}{13} = \frac{66}{13}\]

\[\boxed{\mathbf{5.}}\]

\[\textbf{а)}\ \frac{13}{19} + \frac{6}{19} = \frac{19}{19} = 1\]

\[\textbf{б)}\ \frac{8}{21} + \frac{3}{21} + \frac{5}{21} = \frac{16}{21}\]

\[\textbf{в)}\ \frac{36}{100} - \frac{14}{100} = \frac{22}{100} = \frac{11}{50}\]

\[\textbf{г)}\ \frac{48}{50} - \frac{14}{50} = \frac{34}{50} = \frac{17}{25}\]

\[\textbf{д)}\ \frac{3}{11} + \frac{7}{11} = \frac{10}{11}\]

\[\textbf{е)}\ \frac{18}{23} - \frac{9}{23} = \frac{9}{23}\]

\[\textbf{ж)}\ \frac{36}{48} + \frac{7}{48} - \frac{1}{48} = \frac{42}{48} = \frac{7}{8}\]

\[\textbf{з)}\frac{35}{100} - \frac{9}{100} + \frac{1}{100} = \frac{27}{100}\]

\[\textbf{и)}\ \frac{17}{41} + \frac{14}{41} - \frac{8}{41} = \frac{23}{41}\]

\[\boxed{\mathbf{6.}}\]

\[\textbf{а)}\ 27\ дм = \frac{27}{10}\ м = 2\frac{7}{10}\ м\]

\[\textbf{б)}\ 275\ см = \frac{275}{100}\ м = 2\frac{75}{100}\ м\]

\[\textbf{в)}\ 290\ см = \frac{290}{100}\ м = 2\frac{90}{100}\ м\]

\[\textbf{г)}\ 50\ 000\ \ кг = 50\ т.\]