ГДЗ по математике 5 класс Ерина рабочая тетрадь Часть 1, 2 Часть 1 | Страница 61

\[\boxed{\mathbf{Страница\ 61.\ }\mathbf{Еуроки\ - \ ДЗ\ без\ мороки}}\]

\[\boxed{\mathbf{7.\ }}\]

\[\textbf{а)}\text{\ x} = 9\]

\[\textbf{б)}\ y = 3\]

\[\textbf{в)}\ a = 7\]

\[\textbf{г)}\ z = 9\]

\[\textbf{д)}\ a = 6\]

\[\textbf{е)}\ x = 1\]

\[\textbf{ж)}\ a = 10\]

\[\textbf{з)}\ y = 5\]

\[\textbf{и)}\ x = 3\]

\[к)\ a = 0\]

\[\boxed{\mathbf{8.\ }}\]

\[\textbf{а)}\ (3 + 4)^{2} = 7^{2} = 49\]

\[\textbf{б)}\ 7^{2} + 5^{2} = 49 + 25 = 74\ \]

\[\textbf{в)}\ 8^{3} + 3 = 512 + 3 = 515\ \]

\[\textbf{г)}\ (8 + 2)^{3} = 10^{3} = 1000\ \]

\[\textbf{д)}\ (6 - 2)^{2}\ :(6 - 2) = 4^{2}\ :4 =\]

\[= 16\ :4 = 4\ \]

\[\textbf{е)}\ 9^{3} - 4^{3} = 729 - 64 = 665\ \]

\[\textbf{ж)}\ 4^{2} \cdot 11 = 16 \cdot 11 = 176\ \]

\[\textbf{з)}\ \left( 9^{3} - 5^{3} \right)\ :(8 - 6) =\]

\[= (729 - 125)\ :2 =\]

\[= 604\ :2 = 302\ \]

\[\boxed{\mathbf{9.\ }}\]

\[\textbf{а)}\ 10^{2} = 100\]

\[\textbf{б)}\ 2^{3} = 8\ \]

\[\textbf{в)}\ 8^{2} = 64\ \]

\[\textbf{г)}\ 7^{2} = 49\ \]

\[\textbf{д)}\ 5^{3} = 125\ \]

\[\textbf{е)}\ 11^{2} = 121\]

\[\textbf{ж)}\ 1^{3} = 1\ \]

\[\textbf{з)}\ 0^{2} = 0\ \]

\[\textbf{и)}\ 4^{3} = 64\]

\[\boxed{\mathbf{10.\ }}\]

\[\textbf{а)}\ 2 \cdot 8^{2} - 24 \cdot 5 + 27 =\]

\[= 2 \cdot 64 - 128 + 27 =\]

\[= 128 - 120 + 27 = 35\]

\[\textbf{б)}\ \left( 5^{2} + 7 \cdot 8 \right)\ :\left( 2^{2} + 5 \right) =\]

\[= (25 + 56)\ :(4 + 5) =\]

\[= 81\ :9 = 9\]

\[\textbf{в)}\ 3 \cdot \left( 7^{2} + 15^{2} - 7 \cdot 17 \right) =\]

\[= 3 \cdot (49 + 225 - 119) =\]

\[= 3 \cdot 155 = 465\]

\[\textbf{г)}\ 5 \cdot 8^{2} + 10 \cdot 3^{3} - 16 =\]

\[= 5 \cdot 64 + 10 \cdot 27 - 16 =\]

\[= 320 + 270 - 16 = 574\]

\[\textbf{д)}\ 18^{3}\ :6 + \left( 2^{3} + 4^{2} \right) =\]

\[= 324 \cdot 3 + (8 + 16) =\]

\[= 972 + 24 = 996\]

\[\textbf{е)}\ 94 \cdot 85 - 21^{2} =\]

\[= 7990 - 441 = 7549\]

\[\boxed{\mathbf{11.\ }}\]

\[При\ x = 5:\]

\[38x^{2} - \left( 13x^{2} + 121 \right) =\]

\[= 38x^{2} - 13x^{2} - 121 =\]

\[= 25x^{2} - 121 = 25 \cdot 5^{2} - 121 =\]

\[= 25 \cdot 25 - 121 =\]

\[= 625 - 121 = 504.\]