\[\boxed{\mathbf{981\ (981)}\mathbf{.}\mathbf{\ }Еуроки\ - \ ДЗ\ без\ мороки}\]
\[\textbf{а)}\ \left( \frac{3^{\backslash 6}}{4} + \frac{3^{\backslash 3}}{8} + \frac{5^{\backslash 4}}{6} \right) \cdot 24 = \frac{18 + 9 \cdot 20}{24} \cdot 24 = 47\]
\[\textbf{б)}\ 7 \cdot \frac{2}{3} + 7 \cdot \frac{1}{2} + 7 \cdot \frac{5}{6} = 7 \cdot \left( \frac{2^{\backslash 2}}{3} + \frac{1^{\backslash 3}}{2} + \frac{5}{6} \right) = 7 \cdot \frac{4 + 3 + 5}{6} =\]
\[= 7 \cdot \frac{12}{6} = 7 \cdot 2 = 14\]