ГДЗ по математике 5 класс Мерзляк Задание 777

\[\boxed{\mathbf{777\ (777)}.\ Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1)\ 6\frac{4}{9} + 3\frac{5}{9} =\]

\[= (6 + 3) + \left( \frac{4}{9} + \frac{5}{9} \right) = 9 + \frac{9}{9} =\]

\[= 9 + 1 = 10\]

\[2)\ 10\frac{11}{19} + 5\frac{14}{19} =\]

\[= (10 + 5) + \left( \frac{11}{19} + \frac{14}{19} \right) =\]

\[= 15 + \frac{25}{19} = 15 + 1\frac{6}{19} = 16\frac{6}{19}\]

\[3)\ 2\frac{3}{13} + 2\frac{11}{13} =\]

\[= (2 + 2) + \left( \frac{3}{13} + \frac{11}{13} \right) =\]

\[= 4 + \frac{14}{13} = 4 + 1\frac{1}{13} = 5\frac{1}{13}\]

\[4)\ 1\frac{5}{8} + 3\frac{7}{8} =\]

\[= (1 + 3) + \left( \frac{5}{8} + \frac{7}{8} \right) = 4 + \frac{12}{8} =\]

\[= 4 + 1\frac{4}{8} = 5\frac{4}{8}\]

\[5)\ 1 - \frac{3}{11} = \frac{11}{11} - \frac{3}{11} = \frac{11 - 3}{11} =\]

\[= \frac{8}{11}\]

\[6)\ 1 - \frac{13}{40} = \frac{40}{40} - \frac{13}{40} =\]

\[= \frac{40 - 13}{40} = \frac{27}{40}\]

\[7)\ 4 - 1\frac{4}{7} = 3\frac{7}{7} - 1\frac{4}{7} =\]

\[= (3 - 1) + \left( \frac{7}{7} - \frac{4}{7} \right) = 2 + \frac{3}{7} =\]

\[= 2\frac{3}{7}\]

\[8)\ 10 - 9\frac{3}{10} = 9\frac{10}{10} - 9\frac{3}{10} =\]

\[= (9 - 9) + \left( \frac{10}{10} - \frac{3}{10} \right) =\]

\[= 0 + \frac{7}{10} = \frac{7}{10}\]

\[9)\ 5\frac{2}{7} - 2\frac{5}{7} = 4\frac{9}{7} - 2\frac{5}{7} =\]

\[= (4 - 2) + \left( \frac{9}{7} - \frac{5}{7} \right) = 2 + \frac{4}{7} =\]

\[= 2\frac{4}{7}\]

\[10)\ 14\frac{6}{20} - 8\frac{12}{20} =\]

\[= 13\frac{26}{20} - 8\frac{12}{20} =\]

\[= (13 - 8) + \left( \frac{26}{20} - \frac{12}{20} \right) =\]

\[= 5 + \frac{14}{20} = 5\frac{14}{20}\]

\[11)\ 8\frac{3}{14} - 5\frac{9}{14} = 7\frac{17}{14} - 5\frac{9}{14} =\]

\[= (7 - 5) + \left( \frac{17}{14} - \frac{9}{14} \right) =\]

\[= 2 + \frac{8}{14} = 2\frac{8}{14}\]

\[12)\ 7\frac{10}{21} - 4\frac{16}{21} = 6\frac{31}{21} - 4\frac{16}{21} =\]

\[= (6 - 4) + \left( \frac{31}{21} - \frac{16}{21} \right) =\]

\[= 2 + \frac{15}{21} = 2\frac{15}{21}\]

\[13)\ 14\frac{8}{31} - 6\frac{8}{31} =\]

\[= (14 - 6) + \left( \frac{8}{31} - \frac{8}{31} \right) =\]

\[= 8 + 0 = 8\]

\[= 19\frac{22}{22} - \left( 12\frac{30}{23} - 9\frac{15}{23} \right) =\]

\[= 20 - 3\frac{15}{23} = 19\frac{23}{23} - 3\frac{15}{23} =\]

\[= 16\frac{8}{23}\]