ГДЗ по математике 5 класс Ерина Виленкин рабочая тетрадь Часть 1, 2 Часть 2 | Страница 56

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Год:2023
Тип:рабочая тетрадь
Часть:1, 2
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Страница 56

\[Стр.\ 56.\]

\[\boxed{\mathbf{3.}}\]

\[\textbf{а)}\ 1\ :\frac{1}{7} = 1 \cdot 7 = 7\]

\[5\ :\frac{5}{8} = 5 \cdot \frac{8}{5} = 8\]

\[4\ :\frac{8}{9} = 4 \cdot \frac{9}{8} = \frac{9}{2} = 4\frac{1}{2}\]

\[120\ :\frac{1}{10} = 120 \cdot 10 = 1200\]

\[\textbf{б)}\ \frac{3}{7}\ :\frac{9}{14} = \frac{3}{7} \cdot \frac{14}{9} = \frac{2}{3}\]

\[\frac{3}{10}\ :\frac{8}{11} = \frac{3}{10} \cdot \frac{11}{8} = \frac{33}{80}\]

\[\frac{7}{12}\ :\frac{5}{6} = \frac{7}{12} \cdot \frac{6}{5} = \frac{7}{10}\]

\[\frac{7}{8}\ :\frac{3}{4} = \frac{7}{8} \cdot \frac{4}{3} = \frac{7}{6} = 1\frac{1}{6}\]

\[\textbf{в)}\ 12\ :\frac{5}{8} = 12 \cdot \frac{8}{5} = \frac{96}{5} = 19\frac{1}{5}\]

\[\frac{1}{3}\ :3 = \frac{1}{3} \cdot \frac{1}{3} = \frac{1}{9}\]

\[\frac{5}{7}\ :10 = \frac{5}{7} \cdot \frac{1}{10} = \frac{1}{14}\]

\[\frac{10}{11}\ :5 = \frac{10}{11} \cdot \frac{1}{5} = \frac{2}{11}\]

\[\textbf{г)}\ \frac{1}{200}\ :200 = \frac{1}{200} \cdot \frac{1}{200} =\]

\[= \frac{1}{40000}\]

\[\frac{9}{16}\ :6 = \frac{9}{16} \cdot \frac{1}{6} = \frac{3}{32}\]

\[\frac{84}{121}\ :\frac{63}{110} = \frac{84}{121} \cdot \frac{110}{63} = \frac{4 \cdot 10}{11 \cdot 3} =\]

\[= \frac{40}{33} = 1\frac{7}{33}\]

\[\boxed{\mathbf{4.}}\]

\[\textbf{а)}\ 18\ :10\frac{7}{20} = 18\ :\frac{207}{20} =\]

\[= 18 \cdot \frac{20}{207} = \frac{40}{23} = 1\frac{17}{23}\]

\[4\frac{1}{2}\ :\frac{2}{3} = \frac{9}{2} \cdot \frac{3}{2} = \frac{27}{4} = 6\frac{3}{4}\]

\[5\frac{17}{24}\ :\frac{2}{3} = \frac{137}{24} \cdot \frac{3}{2} = \frac{137}{16} = 8\frac{9}{16}\]

\[\textbf{б)}\ 17\frac{5}{14}\ :2\frac{2}{27} = \frac{243}{14}\ :\frac{56}{27} =\]

\[= \frac{243}{14} \cdot \frac{27}{56} = \frac{6561}{784} = 2\frac{289}{784}\]

\[39\ :9\frac{3}{5} = 39\ :\frac{48}{5} = 39 \cdot \frac{5}{48} =\]

\[= \frac{45}{16} = 2\frac{13}{16}\]

\[\frac{7}{12}\ :3\frac{1}{16} = \frac{7}{12}\ :\frac{49}{16} = \frac{7}{12} \cdot \frac{16}{49} =\]

\[= \frac{4}{21}\]

\[\textbf{в)}\ 63\frac{1}{3}\ :5\frac{2}{11} = \frac{190}{3}\ :\frac{57}{11} =\]

\[= \frac{190}{3} \cdot \frac{11}{57} = \frac{2090}{171} = 12\frac{38}{171}\]

\[6\frac{1}{8}\ :3\frac{1}{3} = \frac{49}{8}\ :\frac{10}{3} = \frac{49}{8} \cdot \frac{3}{10} =\]

\[= \frac{147}{80} = 1\frac{67}{80}\]

\[5\frac{9}{11}\ :13\frac{5}{7} = \frac{64}{11}\ :\frac{96}{7} = \frac{64}{11} \cdot \frac{7}{96} =\]

\[= \frac{14}{33}\]

\[\textbf{г)}\ 32\ :9\frac{3}{5} = 32\ :\frac{48}{5} = 32 \cdot \frac{5}{48} =\]

\[= \frac{10}{3} = 3\frac{1}{3}\]

\[25\frac{5}{7}\ :1\frac{1}{35} = \frac{180}{7}\ :\frac{36}{35} =\]

\[= \frac{180}{7} \cdot \frac{35}{36} = 5 \cdot 5 = 25\]

\[21\frac{7}{9}\ :4\frac{2}{3} = \frac{196}{9}\ :\frac{14}{3} =\]

\[= \frac{196}{9} \cdot \frac{3}{14} = \frac{14}{3} = 4\frac{2}{3}\]

\[\boxed{\mathbf{5.}}\]

\[Мы\ смешанное\ число\ \]

\[заменяем\ суммой\ целой\ и\ \]

\[дробной\ части,потом\ каждую\ \]

\[часть\ делим\ на\ число\ и\ \]

\[находим\ сумму\ результатов\]

\[деления.\]

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