ГДЗ по математике 6 класс Ерина Никольский рабочая тетрадь Часть 1, 2 Часть 1 | Страница 63

\[\mathbf{Страница\ 63.}\]

\[\boxed{\mathbf{5.}}\]

\[\textbf{а)}\ 84 - 53 + 61 - 3 =\]

\[= + (84 - 53 + 61 - 3)\]

\[\textbf{б)}\ 58 + 49 - 34 - 25 =\]

\[= + (58 + 49 - 34 - 25)\]

\[\textbf{в)} - 72 + 38 - 11 + 100 =\]

\[= + ( - 72 + 38 - 11 + 100)\]

\[\textbf{г)} - 17 - 15 + 41 + 19 =\]

\[= + ( - 17 - 15 + 41 + 19)\]

\[\textbf{д)}\ 93 - 102 + 16 - 4 =\]

\[= + (93 - 102 + 16 - 4)\]

\[\textbf{е)} - 100 + 51 - 12 + 32 =\]

\[= + ( - 100 + 51 - 12 + 32)\]

\[\boxed{\mathbf{6.}}\]

\[\textbf{а)}\ 65 - 37 + 19 - 4 =\]

\[= - ( - 65 + 37 - 19 + 4)\]

\[\textbf{б)} - 94 + 51 - 13 + 62 =\]

\[= - (94 - 51 + 13 - 62)\]

\[\textbf{в)}\ 39 + 58 - 130 - 110 =\]

\[= - ( - 39 - 58 + 130 + 110)\]

\[\textbf{г)} - 63 - 79 + 45 + 23 =\]

\[= - (63 + 79 - 45 - 23)\]

\[\textbf{д)}\ 47 - 98 + 12 - 3 =\]

\[= - ( - 47 + 98 - 12 + 3)\]

\[\textbf{е)} - 52 + 42 - 16 + 33 =\]

\[= - (52 - 42 + 16 - 33)\]

\[\boxed{\mathbf{7.}}\]

\[\textbf{а)} - (8 - x) - x =\]

\[= - 8 + x - x = - 8\]

\[\textbf{б)}\ (x - 4) - (x + 5) =\]

\[= x - 4 - x - 5 = - 9\]

\[\textbf{в)} - (y - a - 3) - (4 + a) =\]

\[= - y + a + 3 - 4 - a = - y - 1\]

\[\textbf{г)} - (16 - b + c) + (8 + c) =\]

\[= - 16 + b - c + 8 + c = b - 8\]

\[\boxed{\mathbf{8.}}\]

\[(x - y + 19) + (y - x - 10) =\]

\[= x - y + 19 + y - x - 10 = 9\]

\[Ответ:9.\]

\[\boxed{\mathbf{9.}}\]

\[(a - b - 7) - (6 + a - b) =\]

\[= a - b - 7 - 6 - a + b = - 13\]

\[Ответ:\ - 13.\]

\[\boxed{\mathbf{10.}}\]

\[\textbf{а)}\ 8\frac{4}{9} - x = 6\frac{7}{15}\]

\[x = 8\frac{4}{9} - 6\frac{7}{15}\]

\[x = 8\frac{20}{45} - 6\frac{21}{45}\]

\[x = 7\frac{65}{45} - 6\frac{21}{45}\]

\[x = 1\frac{44}{45}.\]

\[Ответ:1\frac{44}{45}.\]

\[\textbf{б)}\ x\ :1\frac{1}{3} = 1\frac{13}{14} \cdot 2\frac{1}{3}\]

\[x\ :\frac{4}{3} = \frac{27}{14} \cdot \frac{7}{3}\]

\[x\ :\frac{4}{3} = \frac{9}{2}\]

\[x = \frac{9}{2} \cdot \frac{4}{3}\]

\[x = 6.\]

\[Ответ:\ 6.\]