ГДЗ по математике 6 класс Ерина Никольский рабочая тетрадь Часть 1, 2 Часть 1 | Страница 76

\[\mathbf{Страница\ 76.}\]

\[\boxed{\mathbf{1.}}\]

\[- \frac{7}{11};\ - 2\frac{1}{6};\ - 15\frac{4}{9};\]

\[\ - \frac{88}{17};\ - \frac{15}{33}.\]

\[\boxed{\mathbf{2.}}\]

\[\textbf{а)} - ( - 8) \rightarrow - 8\ \]

\[- 5 \rightarrow 5\]

\[\frac{1}{5} \rightarrow - \frac{1}{5}\]

\[\frac{1}{8} \rightarrow - \frac{1}{8}\]

\[\textbf{б)} - ( - 8) \rightarrow \frac{1}{8}\]

\[- 8 \rightarrow - \frac{1}{8}\]

\[- 5 \rightarrow - \frac{1}{5}\]

\[5 \rightarrow \frac{1}{5}\]

\[\boxed{\mathbf{3.}}\]

\[\textbf{а)}\ | - 53| + | - 27| = 80\]

\[\textbf{б)}\ \left| - 1\frac{3}{5} \right| + \left| - \frac{1}{4} \right| =\]

\[= 1\frac{12}{20} + \frac{5}{20} = 1\frac{17}{20}\]

\[\textbf{в)}\ | - 34|\ :\left| - \frac{2}{17} \right| = 34 \cdot \frac{17}{2} =\]

\[= 17 \cdot 17 = 289\]

\[\textbf{г)}\ \left| \frac{7}{8} \right|\ :\left| - \frac{3}{4} \right| = \frac{7}{8} \cdot \frac{4}{3} = \frac{7}{6} = 1\frac{1}{6}\]

\[\textbf{д)}\ | - 27| \cdot \left| \frac{7}{9} \right| = 27 \cdot \frac{7}{9} = 21\]

\[\textbf{е)}\ \left| - \frac{4}{5} \right| \cdot \left| - \frac{5}{8} \right| = \frac{4}{5} \cdot \frac{5}{8} = \frac{1}{2}\ \]

\[\boxed{\mathbf{4.}}\]

\[Число,\ у\ которого\ модуль\ \]

\[больше:\]

\[\textbf{а)} - 8\frac{9}{25}\]

\[\textbf{б)} - \frac{1}{3}\]

\[\textbf{в)}\ 5\frac{7}{9}\]

\[\textbf{г)} - \frac{4}{9}\]

\[\textbf{д)} - 1\frac{2}{5}\]

\[\textbf{е)} - \frac{11}{22}\]

\[\boxed{\mathbf{5.}}\]

\[\textbf{а)}\ \ |y| = \frac{1}{15}\]

\[y = - \frac{1}{15};\ \ y = \frac{1}{15}.\]

\[Ответ:\ - \frac{1}{15};\ \ \frac{1}{15}.\]

\[\textbf{б)}\ | - y| = 5\]

\[y = 5;\ \ y = - 5.\]

\[Ответ:\ - 5;5.\]

\[\textbf{в)} - y = 6\frac{3}{7}\]

\[y = - 6\frac{3}{7}.\]

\[Ответ:\ - 6\frac{3}{7}.\]

\[\boxed{\mathbf{6.}}\]

\[\textbf{б)} - \frac{11}{17} = \frac{- 11}{17}\]

\[\textbf{в)} - \frac{36}{37} = \frac{- 36}{37}\]

\[\textbf{г)} - \frac{1}{3} = \frac{- 1}{3}\]