ГДЗ по математике 6 класс Мерзляк Задание 1108

\[\boxed{\mathbf{1108\ (1099)}\mathbf{.}\mathbf{\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1) - 6 \cdot (2a - 7) + 4 \cdot (5a - 6) =\]

\[{= - 12a + 42 + 20a - 24 = }{= 8a + 18}\]

\[a = - 2,5:\]

\[8a + 18 = 8 \cdot ( - 2,5) + 18 =\]

\[= - 20 + 18 = - 2.\]

\[2) - 1,1 \cdot (2m - 4) -\]

\[- (2 - 3m) - 0,4 \cdot (1 - m) =\]

\[= - + 4,4 - 2 + -\]

\[- 0,4 + = 1,2m + 2\]

\[m = - 4:\]

\[1,2m + 2 = 1,2 \cdot ( - 4) + 2 =\]

\[= - 4,8 + 2 = - 2,8.\]

\[3)\ 1\frac{1}{9} \cdot (3y - 9) -\]

\[- 8\frac{1}{3} \cdot (y - 6) = \frac{10}{3}y -\]

\[- 10 - \frac{25}{3}y + 50 =\]

\[= - \frac{15}{3}y + 40 = - 5y + 40\]

\[y = 3,6:\]

\[- 5y + 40 = - 5 \cdot 3,6 + 40 =\]

\[= - 18 + 40 = 22.\]