ГДЗ по математике 6 класс Виленкин Часть 1, 2 Часть 1. Параграф 2. Действия со смешанными числами Задание 176

\[\boxed{\mathbf{2.}\mathbf{176}}\]

\[\textbf{а)}\ t - \frac{11}{18} = \frac{11}{12} - \frac{5}{9}\]

\[t = \frac{11^{\backslash 3}}{12} - \frac{5^{\backslash 4}}{9} + \frac{11^{\backslash 2}}{18} =\]

\[= \frac{33}{36} - \frac{20}{36} + \frac{22}{36}\]

\[t = \frac{35}{36}.\]

\[\textbf{б)}\frac{4}{5} - \left( \frac{9}{10} - z \right) = \frac{1}{5}\]

\[\frac{9}{10} - z = \frac{4}{5} - \frac{1}{5}\]

\[\frac{9}{10} - z = \frac{3}{5}\]

\[z = \frac{9}{10} - \frac{3^{\backslash 2}}{5} = \frac{9}{10} - \frac{6}{10}\]

\[z = \frac{3}{10} = 0,3.\]

\[\textbf{в)}\ \left( z + \frac{5}{12} \right) - \frac{9}{20} = \frac{11}{15}\]

\[z + \frac{5}{12} = \frac{11}{15} + \frac{9}{20}\]

\[z = \frac{11^{\backslash 4}}{15} + \frac{9^{\backslash 3}}{20} - \frac{5^{\backslash 5}}{12} =\]

\[= \frac{44}{60} + \frac{27}{60} - \frac{25}{60}\]

\[z = \frac{46}{60} = \frac{23}{30}.\]

\[\textbf{г)}\ \frac{4}{5} - \left( x + \frac{1}{60} \right) = \frac{2}{3}\]

\[x + \frac{1}{60} = \frac{4}{5} - \frac{2}{3}\]

\[x = \frac{4^{\backslash 12}}{5} - \frac{2^{\backslash 20}}{3} - \frac{1}{60} =\]

\[= \frac{48}{60} - \frac{40}{60} - \frac{1}{60}\]

\[x = \frac{7}{60}\text{.\ }\]