ГДЗ по математике 6 класс Виленкин Часть 1, 2 Часть 1. Параграф 2. Действия со смешанными числами Задание 245

\[\boxed{\mathbf{2.2}\mathbf{45}}\]

\[\textbf{а)}\ \frac{1^{\backslash 7}}{2} - \frac{2^{\backslash 2}}{7} = \frac{7}{14} - \frac{4}{14} = \frac{3}{14}\]

\[\textbf{б)}\ \frac{5^{\backslash 5}}{6} + \frac{1^{\backslash 3}}{10} = \frac{25}{30} + \frac{3}{30} = \frac{28}{30} =\]

\[= \frac{14}{15}\]

\[\textbf{в)}\ \frac{3^{\backslash 3}}{5} - \frac{4}{15} = \frac{9}{15} - \frac{4}{15} = \frac{5}{15} = \frac{1}{3}\]

\[\textbf{г)}\ \frac{1^{\backslash 9}}{4} + \frac{1^{\backslash 4}}{9} = \frac{9}{36} + \frac{4}{36} = \frac{13}{36}\]

\[\textbf{д)}\ 0 + \frac{4}{11} = \frac{4}{11}\]

\[\textbf{е)}\ \frac{5^{\backslash 5}}{6} + \frac{2^{\backslash 2}}{15} = \frac{25}{30} + \frac{4}{30} = \frac{29}{30}\]

\[\textbf{ж)}\ \frac{31^{\backslash 3}}{60} - \frac{17^{\backslash 4}}{45} = \frac{93}{180} - \frac{68}{180} =\]

\[= \frac{25}{180} = \frac{5}{36}\]

\[\textbf{з)}\ \frac{23^{\backslash 4}}{45} - \frac{29^{\backslash 3}}{60} = \frac{92}{180} - \frac{87}{180} =\]

\[= \frac{5}{180} = \frac{1}{36}\]

\[\textbf{и)}\ \frac{21^{\backslash 5}}{22} + \frac{8^{\backslash 2}}{55} = \frac{105}{110} + \frac{16}{110} =\]

\[= \frac{121}{110} = 1\frac{11}{110} = 1\frac{1}{10} = 1,1\]

\[к)\ \frac{9}{19} - 0 = \frac{9}{19}\]