ГДЗ по математике 6 класс Виленкин Часть 1, 2 Часть 1. Параграф 2. Действия со смешанными числами Задание 467

\[\boxed{\mathbf{2.467}}\]

\[\textbf{а)}\ \frac{2}{7}z = 1\frac{1}{7}\]

\[\frac{2}{7}z = \frac{8}{7}\]

\[z = \frac{8}{7}\ :\frac{2}{7} = \frac{8}{7} \cdot \frac{7}{2}\]

\[z = 4.\]

\[Ответ:z = 4.\]

\[\textbf{б)}\ \frac{3}{5}n = 2\frac{7}{10} - \frac{3}{5}\]

\[\frac{3}{5}n = 2\frac{7}{10} - \frac{6}{10}\]

\[\frac{3}{5}n = 2\frac{1}{10}\]

\[n = \frac{21}{10}\ :\frac{3}{5} = \frac{21}{10} \cdot \frac{5}{3}\]

\[n = \frac{7}{2} = 3,5.\]

\[Ответ:n = 3,5.\]

\[\textbf{в)}\ \frac{4}{9}b + \frac{3}{7} = 1\]

\[\frac{4}{9}b = 1 - \frac{3}{7}\]

\[\frac{4}{9}b = \frac{4}{7}\]

\[b = \frac{4}{7}\ :\frac{4}{9} = \frac{4}{7} \cdot \frac{9}{4}\]

\[b = \frac{9}{7} = 1\frac{2}{7}.\]

\[Ответ:b = 1\frac{2}{7}.\]

\[\textbf{г)}\ \frac{5}{9}m - \frac{1}{2} = \frac{5}{18}\]

\[\frac{5}{9}m = \frac{5}{18} + \frac{9}{18}\]

\[\frac{5}{9}m = \frac{14}{18}\]

\[m = \frac{7}{9}\ :\frac{5}{9} = \frac{7}{9} \cdot \frac{9}{5}\]

\[m = \frac{7}{5} = 1,4.\ \]

\[Ответ:m = 1,4.\]