ГДЗ по математике 6 класс Виленкин Часть 1, 2 Часть 2. Параграф 5. Решение уравнений Задание 39

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Год:2020-2021-2022
Тип:учебник
Часть:1, 2
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Задание 39

\[\boxed{\text{5.\ 39}}\]

\[\textbf{а)}\ 1\ :\frac{1}{2} = 2\]

\[1\ :\left( - \frac{1}{6} \right) = - 6\]

\[1\ :( - 1) = - 1\]

\[1\ :( - 3) = - \frac{1}{3}\]

\[1\ :2 = \frac{1}{2}\]

\[- 6\ :\frac{1}{2} = - 6 \cdot 2 = - 12\]

\[- 6\ \ :\left( - \frac{1}{6} \right) = 6 \cdot 6 = 36\]

\[- 6\ \ :( - 1) = 6\]

\[- 6\ \ :( - 3) = 2\]

\[- 6\ \ :2 = - 3\]

\[\frac{1}{3}\ :\frac{1}{2} = \frac{1}{3} \cdot 2 = \frac{2}{3}\]

\[\frac{1}{3}\ :\left( - \frac{1}{6} \right) = - \frac{1}{3} \cdot 6 = - 2\]

\[\frac{1}{3}\ :( - 1) = - 1\]

\[\frac{1}{3}\ :( - 3) = - \frac{1}{3} \cdot \frac{1}{3} = - \frac{1}{9}\]

\[\frac{1}{3}\ :2 = \frac{1}{3} \cdot \frac{1}{2} = \frac{1}{6}\]

\[0\ :\frac{1}{2} = 0\]

\[0\ :\left( - \frac{1}{6} \right) = 0\]

\[0\ :( - 1) = 0\]

\[0\ :( - 3) = 0\]

\[0\ :2 = 0\]

\[- \frac{1}{2}\ :\frac{1}{2} = - 1\]

\[- \frac{1}{2}\ :\left( - \frac{1}{6} \right) = \frac{1}{2} \cdot 6 = 3\]

\[- \frac{1}{2}\ :( - 1) = \frac{1}{2}\]

\[- \frac{1}{2}\ :( - 3) = \frac{1}{2} \cdot \frac{1}{3} = \frac{1}{6}\]

\[- \frac{1}{2}\ :2 = - \frac{1}{2} \cdot \frac{1}{2} = - \frac{1}{4}\]

\[\textbf{б)} - \frac{3}{4} \cdot 0,5 = - \frac{3}{4} \cdot \frac{1}{2} = - \frac{3}{8}\]

\[- \frac{3}{4} \cdot \frac{1}{4} = - \frac{3}{16}\]

\[- \frac{3}{4} \cdot 2 = - \frac{3}{2} = - 1,5\]

\[- \frac{3}{4} \cdot ( - 1) = \frac{3}{4}\]

\[- \frac{3}{4} \cdot \left( - \frac{1}{2} \right) = \frac{3}{8}\]

\[- \frac{1}{2} \cdot 0,5 = - \frac{1}{2} \cdot \frac{1}{2} = - \frac{1}{4}\]

\[- \frac{1}{2} \cdot \frac{1}{4} = - \frac{1}{8}\]

\[- \frac{1}{2} \cdot 2 = - 1\]

\[- \frac{1}{2} \cdot ( - 1) = \frac{1}{2}\]

\[- \frac{1}{2} \cdot \left( - \frac{1}{2} \right) = \frac{1}{4}\]

\[\frac{1}{2} \cdot 0,5 = \frac{1}{2} \cdot \frac{1}{2} = \frac{1}{4}\]

\[\frac{1}{2} \cdot \frac{1}{4} = \frac{1}{8}\]

\[\frac{1}{2} \cdot 2 = 1\]

\[\frac{1}{2} \cdot ( - 1) = - \frac{1}{2}\]

\[\frac{1}{2} \cdot \left( - \frac{1}{2} \right) = - \frac{1}{4}\]

\[0 \cdot 0,5 = 0\]

\[0 \cdot \frac{1}{4} = 0\]

\[0 \cdot 2 = 0\]

\[0 \cdot ( - 1) = 0\]

\[0 \cdot \left( - \frac{1}{2} \right) = 0\]

\[- 2\frac{1}{4} \cdot 0,5 = - \frac{9}{4} \cdot \frac{1}{2} = - \frac{9}{8} =\]

\[= - 1\frac{1}{8}\]

\[- 2\frac{1}{4} \cdot \frac{1}{4} = - \frac{9}{4} \cdot \frac{1}{4} = - \frac{9}{16}\]

\[- 2\frac{1}{4} \cdot 2 = - \frac{9}{4} \cdot 2 = - \frac{9}{2} = - 4,5\]

\[- 2\frac{1}{4} \cdot ( - 1) = 2\frac{1}{4}\]

\[- 2\frac{1}{4} \cdot \left( - \frac{1}{2} \right) = \frac{9}{4} \cdot \frac{1}{2} = \frac{9}{8} = 1\frac{1}{8}\]

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