ГДЗ по математике 6 класс Ерина Виленкин рабочая тетрадь Часть 1, 2 Часть 1 | Страница 42

\[Страница\ 42.\]

\[9.\ Приведение\ дробей\ \]

\[к\ наименьшему\ общему\ \]

\[знаменателю\]

\[\boxed{\mathbf{1.}}\]

\[\textbf{а)}\frac{5}{9} = \frac{5 \cdot 2}{18} = \frac{10}{18}\]

\[\frac{6}{7} = \frac{6 \cdot 10}{70} = \frac{60}{70}\]

\[\textbf{б)}\frac{11}{16} = \frac{44}{64}\]

\[\frac{12}{13} = \frac{36}{39}\]

\[\textbf{в)}\frac{1}{15} = \frac{6}{90}\]

\[\frac{3}{4} = \frac{240}{320}\]

\[\boxed{\mathbf{2.}}\]

\[\textbf{а)}\frac{7}{9} = \frac{140}{180}\]

\[\textbf{б)}\frac{1}{4} = \frac{45}{180}\]

\[\textbf{в)}\frac{2}{3} = \frac{120}{180}\]

\[\textbf{г)}\frac{5}{18} = \frac{50}{180}\]

\[\boxed{\mathbf{3.}}\]

\[\textbf{а)}\frac{3}{4} = \frac{6}{8}\]

\[\textbf{б)}\frac{5}{6} = \frac{15}{18}\]

\[\textbf{в)}\frac{4}{5} = \frac{24}{30}\]

\[\textbf{г)}\frac{7}{10} = \frac{56}{80}\]

\[\boxed{\mathbf{4.}}\]

\[\textbf{а)}\frac{15}{20} = \frac{3}{4} = \frac{21}{28}\]

\[\frac{21}{28} = \frac{3}{4} = \frac{27}{36}\]

\[\textbf{б)}\frac{16}{40} = \frac{2}{5} = \frac{18}{45}\]

\[\frac{28}{36} = \frac{7}{9} = \frac{63}{81}\]

\[\textbf{в)}\frac{48}{72} = \frac{2}{3} = \frac{200}{300}\]

\[\frac{35}{105} = \frac{1}{3} = \frac{2}{6}\]

\[\boxed{\mathbf{5.}}\]

\[\textbf{а)}\ наименьшему\ общему\ \]

\[кратному.\]

\[\textbf{б)}\ 1)\ НОК;\]

\[2)\ НОК,\ знаменатели,\ \]

\[дополнительный;\]

\[3)\ дополнительный.\]