ГДЗ по математике 6 класс Ерина Виленкин рабочая тетрадь Часть 1, 2 Часть 1 | Страница 49

Авторы:
Год:2023
Тип:рабочая тетрадь
Часть:1, 2
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Страница 49

\[Страница\ 49.\]

\[\boxed{\mathbf{4.}}\]

\[\textbf{а)}\frac{7}{10} + \frac{1}{10} = \frac{8}{10} = \frac{4}{5}\]

\[\textbf{б)}\frac{7}{12} + \frac{1^{\backslash 3}}{4} = \frac{7}{12} + \frac{3}{12} = \frac{10}{12} = \frac{5}{6}\]

\[\textbf{в)}\frac{1^{\backslash 3}}{5} + \frac{2}{15} = \frac{3}{15} + \frac{2}{15} = \frac{5}{15} = \frac{1}{3}\]

\[\textbf{г)}\frac{5^{\backslash 3}}{6} + \frac{1^{\backslash 2}}{9} = \frac{15}{18} + \frac{2}{18} = \frac{17}{18}\]

\[\textbf{д)}\frac{2^{\backslash 4}}{9} + \frac{1^{\backslash 3}}{12} = \frac{8}{36} + \frac{3}{36} = \frac{11}{36}\]

\[\textbf{е)}\frac{7^{\backslash 5}}{24} + \frac{1^{\backslash 2}}{60} = \frac{35}{120} + \frac{2}{120} = \frac{37}{120}\]

\[\textbf{ж)}\frac{1^{\backslash 3}}{42} + \frac{2^{\backslash 2}}{63} = \frac{3}{126} + \frac{4}{126} =\]

\[= \frac{7}{126} = \frac{1}{18}\]

\[\textbf{з)}\frac{5^{\backslash 5}}{12} + \frac{3^{\backslash 3}}{20} = \frac{25}{60} + \frac{9}{60} = \frac{34}{60} =\]

\[= \frac{17}{30}\]

\[\boxed{\mathbf{5.}}\]

\[\textbf{а)}\frac{7}{8} - \frac{3^{\backslash 2}}{4} = \frac{7}{8} - \frac{6}{8} = \frac{1}{8}\]

\[\textbf{б)}\frac{9}{10} - \frac{2^{\backslash 2}}{5} = \frac{9}{10} - \frac{5}{10} = \frac{5}{10} = \frac{1}{2}\]

\[\textbf{в)}\frac{3^{\backslash 3}}{5} - \frac{4}{15} = \frac{9}{15} - \frac{4}{15} = \frac{5}{15} = \frac{1}{3}\]

\[\textbf{г)}\frac{7^{\backslash 7}}{8} - \frac{6^{\backslash 8}}{7} = \frac{49}{56} - \frac{48}{56} = \frac{1}{56}\]

\[\textbf{д)}\frac{7^{\backslash 5}}{12} - \frac{8^{\backslash 4}}{15} = \frac{35}{60} - \frac{32}{60} = \frac{3}{60} =\]

\[= \frac{1}{20}\]

\[\textbf{е)}\frac{25^{\backslash 2}}{39} - \frac{15^{\backslash 3}}{26} = \frac{50}{78} - \frac{45}{78} = \frac{5}{78}\]

\[\textbf{ж)}\frac{7^{\backslash 5}}{15} - \frac{8^{\backslash 3}}{25} = \frac{35}{75} - \frac{24}{75} = \frac{11}{75}\]

\[\textbf{з)}\frac{7^{\backslash 4}}{45} - \frac{7^{\backslash 3}}{60} = \frac{28}{180} - \frac{21}{180} = \frac{7}{180}\]

\[\boxed{\mathbf{6.}}\]

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