ГДЗ по математике 6 класс Ерина Виленкин рабочая тетрадь Часть 1, 2 Часть 2 | Страница 57

\[Стр.\ 57.\]

\[\boxed{\text{2.}\text{\ }}\]

\[\textbf{а)} - 48\ :6 < 0\]

\[32\ :( - 4) < 0\]

\[- 42\ :( - 3) > 0\]

\[16\ :( - 8) < 0\]

\[\textbf{б)} - 72\ :( - 9) > 0\]

\[- 52\ :2 < 0\]

\[81\ :( - 9) < 0\]

\[- 36\ :( - 3) > 0\]

\[\textbf{в)} - 1\ :( - 1) > 0\]

\[5\ :( - 1) < 0\]

\[- 7\ :( - 1) > 0\]

\[0\ :( - 1) = 0\]

\[\boxed{\text{3.}\text{\ }}\]

\[\textbf{а)} - 16\ :2 = - 8\]

\[36\ :( - 4) = - 9\]

\[- 55\ :( - 5) = 11\]

\[12\ :3 = 4\]

\[\textbf{б)} - 6\ :( - 1) = 6\]

\[4\ :( - 1) = - 4\]

\[- 7\ :( - 7) = 1\]

\[- 5\ :5 = - 1\]

\[\textbf{в)}\ 0\ :( - 4) = 0\]

\[- 1\ :( - 1) = 1\]

\[- 6\ :6 = - 1\]

\[7\ :( - 7) = - 1\]

\[\boxed{\text{4.}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

\[- 72\ :18 = - 4\]

\[30\ :( - 15) = - 2\]

\[- 45\ :( - 9) = 5\]

\[360\ :( - 9) = - 40\]

\[- 20\ :4 = - 5\]

\[- 24\ :( - 2) = 12\]

\[- 36\ :( - 4) = 9\]

\[14\ :( - 7) = - 2\]

\[77\ :( - 7) = - 11\]

\[- 30\ :2 = - 15\]

\[- 45\ :( - 5) = 9\]

\[0\ :( - 3) = 0\]

\[\ \boxed{\mathbf{5.}}\]

\[\textbf{а)} - 7\ :( - 3) = \frac{7}{3} = 2\frac{1}{3}\]

\[- 6\ :\frac{6}{11} = - 6 \cdot \frac{11}{6} = - 11\]

\[\textbf{б)}\ 4\ :( - 20) = - \frac{4}{20} = - \frac{1}{5}\]

\[3\frac{3}{7}\ :( - 8) = \frac{24}{7} \cdot \left( - \frac{1}{8} \right) = - \frac{3}{7}\]

\[\textbf{в)} - 8\ :( - 5) = \frac{8}{5} = 1\frac{3}{5}\]

\[\left( - 3\frac{1}{2} \right)\ :\left( - \frac{2}{3} \right) = \frac{7}{2} \cdot \frac{3}{2} = \frac{21}{4} =\]

\[= 5\frac{1}{4}\]

\[\textbf{г)} - \frac{3}{8}\ :\frac{1}{4} = - \frac{3}{8} \cdot 4 = - \frac{3}{2} =\]

\[= - 1\frac{1}{2}\]

\[\frac{3}{16}\ :\left( - \frac{5}{12} \right) = - \frac{3}{16} \cdot \frac{12}{5} = - \frac{9}{20}\]

\[\textbf{д)} - \frac{1}{5}\ :\left( - \frac{3}{4} \right) = \frac{1}{5} \cdot \frac{4}{3} = \frac{4}{15}\]

\[- 3\frac{1}{4}\ :( - 1) = 3\frac{1}{4}\]

\[\textbf{е)}\frac{4}{15}\ :\left( - 3\frac{1}{15} \right) = - \frac{4}{15}\ :\frac{46}{15} =\]

\[= - \frac{4}{15} \cdot \frac{15}{46} = - \frac{2}{23}\]

\[- 1\frac{2}{3}\ :\left( - 1\frac{1}{10} \right) = \frac{5}{3}\ :\frac{11}{10} =\]

\[= \frac{5}{3} \cdot \frac{10}{11} = \frac{50}{33} = 1\frac{17}{33}\]