Контрольные задания >
32.6.1) \(\frac{4}{9} + \frac{4}{3}a + a^{2};\)
3) \(\frac{16}{49} + \frac{8}{7}c + c^{2};\)
5) \(m^{2} - \frac{22}{13}mn + \frac{121}{169}n^{2};\)
32.7. 1) \(\frac{25}{4} + 5x + x^{2};\)
3) \(\frac{49}{36} - \frac{7}{3}z + z^{2};\)
5) \(m^{2} + \frac{11}{6}m + \frac{121}{144};\)
Вопрос:
32.6.1) \(\frac{4}{9} + \frac{4}{3}a + a^{2};\)
3) \(\frac{16}{49} + \frac{8}{7}c + c^{2};\)
5) \(m^{2} - \frac{22}{13}mn + \frac{121}{169}n^{2};\)
32.7. 1) \(\frac{25}{4} + 5x + x^{2};\)
3) \(\frac{49}{36} - \frac{7}{3}z + z^{2};\)
5) \(m^{2} + \frac{11}{6}m + \frac{121}{144};\)
Смотреть решения всех заданий с листаОтвет:
32.6.
-
$$\frac{4}{9} + \frac{4}{3}a + a^{2} = (\frac{2}{3})^{2} + 2 \cdot \frac{2}{3} \cdot a + a^{2} = (\frac{2}{3} + a)^{2}$$
Ответ: $$(\frac{2}{3} + a)^{2}$$
-
$$\frac{16}{49} + \frac{8}{7}c + c^{2} = (\frac{4}{7})^{2} + 2 \cdot \frac{4}{7} \cdot c + c^{2} = (\frac{4}{7} + c)^{2}$$
Ответ: $$(\frac{4}{7} + c)^{2}$$
-
$$m^{2} - \frac{22}{13}mn + \frac{121}{169}n^{2} = m^{2} - 2 \cdot m \cdot \frac{11}{13}n + (\frac{11}{13}n)^{2} = (m - \frac{11}{13}n)^{2}$$
Ответ: $$(m - \frac{11}{13}n)^{2}$$
32.7.
-
$$\frac{25}{4} + 5x + x^{2} = (\frac{5}{2})^{2} + 2 \cdot \frac{5}{2} \cdot x + x^{2} = (\frac{5}{2} + x)^{2}$$
Ответ: $$(\frac{5}{2} + x)^{2}$$
-
$$\frac{49}{36} - \frac{7}{3}z + z^{2} = (\frac{7}{6})^{2} - 2 \cdot \frac{7}{6} \cdot z + z^{2} = (\frac{7}{6} - z)^{2}$$
Ответ: $$(\frac{7}{6} - z)^{2}$$
-
$$m^{2} + \frac{11}{6}m + \frac{121}{144} = m^{2} + 2 \cdot m \cdot \frac{11}{12} + (\frac{11}{12})^{2} = (m + \frac{11}{12})^{2}$$
Ответ: $$(m + \frac{11}{12})^{2}$$
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