(3$$\frac{1}{4}$$+1$$\frac{1}{6}$$⋅1$$\frac{5}{9}$$):2$$\frac{2}{7}$$+$$\frac{2}{3}$$

Ответ: $$\frac{83}{24}$$

1) 1$$\frac{1}{6}$$⋅1$$\frac{5}{9}$$ =$$\frac{7}{6}$$⋅$$\frac{14}{9}$$ =$$\frac{98}{54}$$ =$$\frac{49}{27}$$

2) 3$$\frac{1}{4}$$+$$\frac{49}{27}$$ =$$\frac{13}{4}$$+$$\frac{49}{27}$$ =$$\frac{351+196}{108}$$ =$$\frac{547}{108}$$

3) $$\frac{547}{108}$$ : 2$$\frac{2}{7}$$ =$$\frac{547}{108}$$ :$$\frac{16}{7}$$ =$$\frac{547}{108}$$\times$$\frac{7}{16}$$ =$$\frac{3829}{1728}$$

4) $$\frac{3829}{1728}$$+$$\frac{2}{3}$$ =$$\frac{3829+1152}{1728}$$ =$$\frac{4981}{1728}$$ =2$$\frac{1525}{1728}$$

Ответ: 2$$\frac{1525}{1728}$$