2) (\frac{5}{10} - 3\frac{3}{5} \cdot \frac{4}{5}) \cdot \frac{13}{38} + \frac{5}{84} + 2\frac{1}{12} \cdot \frac{4}{15} ;

2)

$$(\frac{5}{10} - 3\frac{3}{5} \cdot \frac{4}{5}) \cdot \frac{13}{38} + \frac{5}{84} + 2\frac{1}{12} \cdot \frac{4}{15} = (\frac{1}{2} - \frac{18}{5} \cdot \frac{4}{5}) \cdot \frac{13}{38} + \frac{5}{84} + \frac{25}{12} \cdot \frac{4}{15} = $$

$$=(\frac{1}{2} - \frac{72}{25}) \cdot \frac{13}{38} + \frac{5}{84} + \frac{5}{3} \cdot \frac{1}{3} = (\frac{25}{50} - \frac{144}{50}) \cdot \frac{13}{38} + \frac{5}{84} + \frac{5}{9} =$$

$$=-\frac{119}{50} \cdot \frac{13}{38} + \frac{5}{84} + \frac{5}{9} = -\frac{1547}{1900} + \frac{5}{84} + \frac{5}{9} = -\frac{1547}{1900} + \frac{5 \cdot 3}{84 \cdot 3} + \frac{5\cdot 28}{9 \cdot 28} =$$

$$= -\frac{1547}{1900} + \frac{15}{252} + \frac{140}{252} = -\frac{1547}{1900} + \frac{155}{252}= -\frac{1547}{1900} + \frac{155 \cdot 475}{252 \cdot 475} = -\frac{1547}{1900}+ \frac{73625}{119700} = -\frac{1547}{1900}+ \frac{73625}{119700} =$$

$$= \frac{-1547 \cdot 63}{1900 \cdot 63}+ \frac{73625}{119700} = \frac{-97461}{119700}+ \frac{73625}{119700} = \frac{-23836}{119700}= \frac{-5959}{29925}$$

Ответ: $$\frac{-5959}{29925}$$