32. (\frac{2}{5}x²y). (-\frac{5}{4}xy²).

$$\frac{2}{5}x^2y \cdot (-\frac{5}{4}xy^2) = - \frac{2 \cdot 5}{5 \cdot 4} x^{2+1} y^{1+2} = - \frac{2}{4} x^3 y^3 = - \frac{1}{2} x^3 y^3$$

Ответ: $$- \frac{1}{2} x^3 y^3$$