2. ($$\frac{x}{y}-\frac{y}{x}$$) $$\cdot$$ $$\frac{5xy}{x-y}$$ = $$\frac{x^2-y^2}{xy}$$\cdot$$\frac{5xy}{x-y}$$ = $$\frac{(x-y)(x+y)5xy}{xy(x-y)}$$ = 5(x+y) = 5x+5y
Ответ: 5x+5y