8) $$\left(8 - 2\frac{1}{7} \cdot 3\frac{1}{9}\right) \cdot \frac{27}{44} = \left(8 - \frac{2 \cdot 7 + 1}{7} \cdot \frac{3 \cdot 9 + 1}{9}\right) \cdot \frac{27}{44} = \left(8 - \frac{14 + 1}{7} \cdot \frac{27 + 1}{9}\right) \cdot \frac{27}{44} = \left(8 - \frac{15}{7} \cdot \frac{28}{9}\right) \cdot \frac{27}{44} = \left(8 - \frac{15 \cdot 28}{7 \cdot 9}\right) \cdot \frac{27}{44} = \left(8 - \frac{5 \cdot 4}{1 \cdot 3}\right) \cdot \frac{27}{44} = \left(8 - \frac{20}{3}\right) \cdot \frac{27}{44} = \left(\frac{8 \cdot 3}{3} - \frac{20}{3}\right) \cdot \frac{27}{44} = \frac{24 - 20}{3} \cdot \frac{27}{44} = \frac{4}{3} \cdot \frac{27}{44} = \frac{4 \cdot 27}{3 \cdot 44} = \frac{1 \cdot 9}{1 \cdot 11} = \frac{9}{11}$$
Ответ: $$\frac{9}{11}$$